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⚛️ IONIC BONDING & LATTICE ENERGY ⚛️

Coulombic attraction · NaCl rock-salt lattice · Born-Landé · Born-Haber cycle
CHEMSIM v1.0

⚡ INTERACTIVE SIMULATION

🧊 Rock-Salt Lattice
⚡ Single Ion Pair
🔢 Madelung Construction
🔄 Born-Haber Cycle
📊 Periodic Trends
U(r) Curve
Madelung Sum
Born-Haber Bars
Lattice E vs Z
LATTICE ENERGY U₀
-787 kJ/mol
EQUILIBRIUM r₀
282 pm
CHARGE PRODUCT |Z₊Z₋|
1
MADELUNG M
1.7476
BORN EXPONENT n
9.0
COORDINATION
6:6
Preset Salt
Cation charge Z₊+1
Anion charge |Z₋|1
Cation radius r₊ (pm)102
Anion radius r₋ (pm)181
Born exponent n9.0
Animation speed1.0×
Show ion labels
Show partial charges
Show field lines
Vibrate (thermal)
Cutaway view

💡 THE IDEA, STEP BY STEP

START — THE EVERYDAY PICTURE
Table salt is nothing but sodium and chlorine, yet it forms hard little cubic crystals that don't melt until a scorching 801 °C. The reason is the oldest rule in electricity: opposite charges pull together, like charges push apart. A sodium atom hands one electron to a chlorine atom, leaving a positive $\text{Na}^+$ and a negative $\text{Cl}^-$ — and those opposite charges grip each other hard.
BUILD — PUTTING A NUMBER ON IT
How hard? Coulomb's law says the energy of a single ion pair drops as the charges grow and the gap shrinks: $U \approx -\dfrac{k\,Z_+Z_-e^2}{r_0}$. Here $Z_+$ and $Z_-$ are the ion charges (both $1$ for NaCl), $r_0$ is the centre-to-centre distance, and $k$ bundles up the electrical constants. For NaCl, $r_0 = 102 + 181 = 283$ pm, which works out to about $-490$ kJ for every mole of pairs — already a huge amount of electrical glue. Double both charges (as in MgO) and that pull quadruples.
DEEPEN — THE WHOLE LATTICE
But an ion is never glued to just one partner — it sits inside a 3-D lattice of neighbours, some attracting and some repelling. Adding up that infinite chequerboard gives the Madelung constant $M \approx 1.7476$ for rock-salt, which boosts the binding by about 75 %. The ions still cannot collapse into each other: their filled electron shells push back through the Born repulsion $B/r^{\,n}$. Balancing attraction against repulsion at $dU/dr = 0$ gives the full Born–Landé equation $U_0 = -\dfrac{N_A\,M\,|Z_+Z_-|\,e^2}{4\pi\varepsilon_0\,r_0}\!\left(1-\tfrac{1}{n}\right)$. The sliders map straight onto it: $Z_+$ and $Z_-$ set the charge product, $r_+ + r_-$ sets $r_0$, and $n$ tunes the repulsion correction.
TRY THIS IN THE SIM ABOVE
Switch the preset from NaCl to MgO and watch $U_0$ leap roughly four-fold as the charge product climbs from $1{\times}1$ to $2{\times}2$. Then slide both ionic radii upward and see $U_0$ shrink as $r_0$ grows. Finally open the U(r) Curve graph and drag the Born exponent $n$ from $5$ to $12$: notice how the bottom of the well barely moves — direct proof that $r_0$ and $M$, not $n$, set the strength of the bond.

📐 EQUATION DERIVATION

Born–Landé Equation for Lattice Energy
$$ U_0 = -\frac{N_A \, M \, |Z_+ Z_-| \, e^2}{4\pi\varepsilon_0 \, r_0}\left(1 - \frac{1}{n}\right) $$

The lattice energy $U_0$ is the energy released when one mole of an ionic crystal is formed from gaseous ions at infinite separation. It is the single most important quantity in ionic-bonding thermodynamics — it determines melting points, solubilities, and the very stability of an ionic compound.

Symbol Definitions

SymbolMeaningUnit (SI)
$U_0$Lattice energy (formation, negative)J/mol or kJ/mol
$N_A$Avogadro's number = 6.022×10²³mol⁻¹
$M$Madelung constant (geometry-dependent)dimensionless
$Z_+, Z_-$Integer charges of cation, aniondimensionless
$e$Elementary charge = 1.602×10⁻¹⁹C
$\varepsilon_0$Vacuum permittivity = 8.854×10⁻¹²C²·N⁻¹·m⁻²
$r_0$Equilibrium internuclear distance ($r_+ + r_-$)m (or pm)
$n$Born exponent (Pauli repulsion)dimensionless (5–12)

Step-by-Step Derivation

STEP 1 — Coulomb potential of one ion pair
The electrostatic potential energy between a cation ($+Z_+e$) and anion ($-Z_-e$) at distance $r$ is: $$ V_{\text{pair}}(r) = -\frac{Z_+ Z_- e^2}{4\pi\varepsilon_0 \, r} $$ The minus sign comes from opposite charges attracting.
STEP 2 — Sum over the entire lattice (Madelung)
In a crystal, each ion is surrounded by nearest-neighbour counter-ions, second-nearest co-ions (repulsive), third-nearest counter-ions, and so on. The infinite alternating series converges to the Madelung constant $M$: $$ M = \sum_{i \neq j} \pm \frac{r_0}{r_{ij}} \approx 1.7476 \text{ for NaCl} $$ So the Coulombic energy per ion-pair becomes $V_{\text{Coul}} = -\frac{M\,Z_+Z_-e^2}{4\pi\varepsilon_0\,r_0}$.
STEP 3 — Add Pauli repulsion (Born term)
Pure $1/r$ attraction would collapse the lattice to a point. Closed-shell electron clouds repel at short range; Born modelled this empirically as $V_{\text{rep}} = B/r^n$ where $n$ is the Born exponent (≈ 5 for He, 7 for Ne, 9 for Ar/Cu⁺, 12 for Xe). $$ V_{\text{total}}(r) = -\frac{M\,Z_+Z_-e^2}{4\pi\varepsilon_0\,r} + \frac{B}{r^n} $$
STEP 4 — Find equilibrium ($dV/dr = 0$)
$$ \frac{dV}{dr}\bigg|_{r_0} = \frac{M\,Z_+Z_-e^2}{4\pi\varepsilon_0\,r_0^2} - \frac{nB}{r_0^{n+1}} = 0 $$ Solving for $B$: $$ B = \frac{M\,Z_+Z_-e^2 \, r_0^{n-1}}{4\pi\varepsilon_0 \, n} $$
STEP 5 — Substitute back & multiply by $N_A$
Putting $B$ into $V_{\text{total}}(r_0)$ and converting from per-pair to per-mole gives the famous Born-Landé equation: $$ \boxed{\,U_0 = -\frac{N_A \, M \, |Z_+ Z_-| \, e^2}{4\pi\varepsilon_0 \, r_0}\left(1 - \frac{1}{n}\right)\,} $$ The factor $(1 - 1/n)$ shows that Pauli repulsion reduces the binding energy by ~10–15%.
STEP 6 — Born-Haber cycle (alternative experimental route)
Hess's law lets us measure $U_0$ indirectly: $\Delta H_f^\circ = \Delta H_{\text{sub}} + \tfrac{1}{2}D + IE - EA + U_0$. Comparing experimental $U_0$ with Born-Landé tests the ionic model — large deviations (e.g. AgCl, ZnS) indicate covalent character.

Mapping to Simulation

Worked Example — NaCl

For NaCl: $r_0 = 102 + 181 = 283$ pm = $2.83 \times 10^{-10}$ m, $M = 1.7476$, $|Z_+Z_-| = 1$, $n = 9$.

$$ U_0 = -\frac{(6.022\times 10^{23})(1.7476)(1)(1.602\times 10^{-19})^2}{4\pi(8.854\times 10^{-12})(2.83\times 10^{-10})}\left(1-\tfrac{1}{9}\right) $$ $$ U_0 \approx -755 \text{ kJ/mol} \quad (\text{exp: } -787 \text{ kJ/mol}) $$

The small ~4% gap is the covalent contribution not captured by a purely ionic model.

📚 Reference: Housecroft & Sharpe — Inorganic Chemistry, 5th Ed., Chapter 6.16: "The Born–Landé Equation"; Atkins & de Paula — Physical Chemistry, 11th Ed., Section 18B.1: "Lattice enthalpy"; Silberberg — Chemistry: The Molecular Nature of Matter and Change, Ch. 9.2: "The Born-Haber Cycle".

❓ FREQUENTLY ASKED QUESTIONS

📚 Recommended Resource: LibreTexts Chemistry — "Lattice Energy: The Born-Haber Cycle" (chem.libretexts.org); Chemguide.co.uk — Jim Clark's "Lattice Enthalpies" series.

⚠️ COMMON MISCONCEPTIONS

📚 Reference: Taber, K. S. — Chemical Misconceptions: Prevention, Diagnosis and Cure, Royal Society of Chemistry, 2002, Vol. II, Ch. 2: "Ionic bonding"; Boo, H.-K. — J. Chem. Educ. (1998), "Students' Understanding of Chemical Bonds and the Energetics of Chemical Reactions."